JEE Mains · Maths · STD 11 - 7. binomial theoram
Let \(\alpha>0, \beta>0\) be such that \(\alpha^{3}+\beta^{2}=4 .\) If the maximum value of the term independent of \(x\) in the binomial expansion of \(\left(\alpha x^{\frac{1}{9}}+\beta x^{-\frac{1}{6}}\right)^{10}\) is \(10 k\) then \(\mathrm{k}\) is equal to
- A \(176\)
- B \(336\)
- C \(352\)
- D \(84\)
Answer & Solution
Correct Answer
(B) \(336\)
Step-by-step Solution
Detailed explanation
Let \(t_{\mathrm{r}}+1\) denotes \(\mathrm{r}+1 \mathrm{th}\) term of \(\left(\alpha \mathrm{x}^{\frac{1}{9}}+\beta \mathrm{x}^{-\frac{1}{6}}\right)^{10}\)…
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