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JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry

यदि \(\left[ Cu \left( H _2 O \right)_4\right]^{2+} d - d\) संक्रमण के लिए \(600 nm\) तरंगदैर्ध्य वाले प्रकाश का अवशोपण करता है, तो \(\left[ Cu \left( H _2 O \right)_6\right]^{2+}\) के लिए अप्फलकीय-क्रिस्टल क्षेत्र विपाटन ऊर्जा \(........\times 10^{-21}\,J\) होगी। (निकटतम पूर्णांक) (दिया है : \(h =6.63 \times 10^{-34} Js\) एवं \(\left.c =3.08 \times 10^8 ms ^{-1}\right)\)

  1. A \(766\)
  2. B \(852\)
  3. C \(412\)
  4. D \(344\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(766\)

Step-by-step Solution

Detailed explanation

\(\Delta_{ t }=\frac{ hc }{\lambda}=\frac{6.63 \times 10^{-34} \times 3.08 \times 10^{8}}{600 \times 10^{-9}}\) \(=\frac{6.63 \times 3.08 \times 10^{-17}}{600}\) \(=0.034034 \times 10^{-17}\) \(=340.34 \times 10^{-21} \,J\) \(\Delta_{0}=\frac{9}{4} \Delta_{ t }\)…
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