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JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry

सूची-I का सूची-II से मिलान करें
सूची-I (संकुल)सूची-II (केवल प्रचक्रण चुंबकीय आघूर्ण B.M. में)
\((A)\) \({\left[\mathrm{Cr}\left(\mathrm{NH}_5\right)_0\right]^{3+}}\)\((I)\) \(4.90\)
\((B)\) \({\left[\mathrm{NiCl}_4\right]^{2-}}\)\((II)\) \(3.87\)
\((C)\) \({\left[\mathrm{CoF}_6\right]^{3-}}\)\((III)\) \(0.0\)
\((D)\) \({\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}}\)\((IV)\) \(2.83\)
नीचे दिए गए विकल्पों में से सही उत्तर चुनें:

  1. A \((A)-(I), (B)-(IV), (C)-(II), (D)-(III)\)
  2. B \((A)-(IV), (B)-(III), (C)-(I), (D)-(II)\)
  3. C \((A)-(II), (B)-(IV), (C)-(I), (D)-(III)\)
  4. D \((A)-(II), (B)-(III), (C)-(I), (D)-(IV)\)
Verified Solution

Answer & Solution

Correct Answer

(C) \((A)-(II), (B)-(IV), (C)-(I), (D)-(III)\)

Step-by-step Solution

Detailed explanation

\((A)\) \({\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]^{3+}}\) \(\mathrm{Cr}^{3+}: 3 \mathrm{~d}^3\) \(\mathrm{n}=3\) (अयुग्मित इलेक्ट्रॉन) \(\mu \simeq 3.87 \text { B.M. (II) }\) \((B)\) \({\left[\mathrm{NiCl}_4\right]^{2-}}\) \(\mathrm{Ni}^{2+}: 3 \mathrm{~d}^8\)…
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