निम्न में से कौन सा समीकरण थर्मोडायनामिक्स के प्रथम सिद्धान्त को दिये गये प्रक्रमों के लिए, जिसमें आदर्श गैस है, सही रूप में प्रस्तुत नहीं करता है (मान लें कि अप्रसारण कार्य शून्य है)

A समायतनिक प्रक्रम : \(\Delta U = q\)
B रुद्धोष्म प्रक्रम : \(\Delta U =- W\)
C चक्रीय प्रक्रम : \(q=-w\)
D समतापी प्रक्रम : \(q=-w\)

Verified Solution

Answer & Solution

Correct Answer

(B) रुद्धोष्म प्रक्रम : \(\Delta U =- W\)

Step-by-step Solution

Detailed explanation

According to the first law of thermodynamics \(q=\Delta U-w\) For cyclic process : \(\Delta U = 0 \Rightarrow q = - w\) For isothermal process : \(\Delta U = 0 \Rightarrow q = - w\) For adiabatic process : \(q = 0 \Rightarrow \Delta U = W\) For isochoric process :…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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