ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 11 - 12. limits

\(\mathop {\lim }\limits_{x \to 0} \frac{{{{(27 + x)}^{_{\frac{1}{3}}}} - 3}}{{9 - {{(27 + x)}^{\frac{2}{3}}}}}\) = 

  1. A \(-\frac {1}{3}\)
  2. B \(\frac {1}{6}\)
  3. C \(-\frac {1}{6}\)
  4. D \(\frac {1}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-\frac {1}{6}\)

Step-by-step Solution

Detailed explanation

Let \(L = \,\,\,\mathop {\lim }\limits_{x \to 0} \frac{{{{\left( {27 + x} \right)}^{\frac{1}{3}}} - 3}}{{9 - {{\left( {27 + x} \right)}^{\frac{2}{3}}}}}\) Here \('L'\) is in the indeterminate from i.e.,\(\frac{0}{0}\) \(\therefore \) usinh the \(L'\) Hosoital rule we get:…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app