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JEE Mains · Maths · STD 12 - 10. vector algebra

ધારો કે  \(\vec \alpha \, = \,3\hat i\, + \hat j\) અને \(\vec \beta \, = \,2\hat i\, - \hat j + 3\hat k\) આપેલ છે . જો \(\vec \beta \, = \,{\vec \beta _1} - {\vec \beta _2},\) કે જ્યાં  \({\vec \beta _1}\) એ \(\vec \alpha \) ને સમાંતર અને \(\vec \beta_2 \) એ \(\vec \alpha \) ને લંબ હોય તો \({\vec \beta _1} \times {\vec \beta _2}\) મેળવો.

  1. A \(\frac{1}{2}( - 3\hat i + 9\hat j + 5\hat k)\)
  2. B \(\frac{1}{2}(  3\hat i - 9\hat j + 5\hat k)\)
  3. C \(- 3\hat i + 9\hat j + 5\hat k\)
  4. D \(3\hat i - 9\hat j - 5\hat k\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1}{2}( - 3\hat i + 9\hat j + 5\hat k)\)

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Detailed explanation

\(\vec{\alpha}=3 \hat{i}+\hat{j}\) \(\vec{\beta}=2 \hat{i}-\hat{j}+3 \hat{k}\) \(\vec{\beta}=\vec{\beta}_{1}-\vec{\beta}_{2}\) \(\overrightarrow {{\beta _1}} = \lambda (3\hat i + \hat j),\overrightarrow {{\beta _2}} = \lambda (3\hat i + \hat j) - 2\hat i + \hat j - 3\hat k\)…
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