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JEE Mains · Maths · STD 12 - 7.2 definite integral

જો \(\mathrm{f} \  (0, \infty) \rightarrow \mathrm{R}\) બે વિધેયો \(\mathrm{f}(\mathrm{x})=\int_{-\mathrm{x}}^{\mathrm{x}}\left(|\mathrm{t}|-\mathrm{t}^2\right) \mathrm{e}^{-\mathrm{t}^2} \mathrm{dt}\) અને \(g(x)=\int_{-x}^x t^{1 / 2} e^{-t} d t\) થી વ્યાખ્યાયિત છે. તો \(\left(f\left(\sqrt{\log _e 9}\right)+g\left(\sqrt{\log _e 9}\right)\right) =\) ...........

  1. A \(6\)
  2. B \(9\)
  3. C \(8\)
  4. D \(10\)
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Answer & Solution

Correct Answer

(C) \(8\)

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Detailed explanation

\(\mathrm{f}(\mathrm{x})=\int_{-\mathrm{x}}^{\mathrm{x}}\left(|\mathrm{t}|-\mathrm{t}^2\right) \mathrm{e}^{-\mathrm{t}^2} \mathrm{dt}\)…
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