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JEE Mains · Maths · STD 12 - 7.2 definite integral

Let \(f, g:(0, \infty) \rightarrow R\) be two functions defined by \(f(x)=\int_{-x}^x\left(|t|-t^2\right) e^{-t^2} d t\) and \(g(x)=\int_0^{x^2} t^{1 / 2} e^{-t} d t\). Then the value of \(\left(\mathrm{f}\left(\sqrt{\log _{\mathrm{e}} 9}\right)+\mathrm{g}\left(\sqrt{\log _{\mathrm{e}} 9}\right)\right)\) is

  1. A \(6\)
  2. B \(9\)
  3. C \(8\)
  4. D \(10\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(8\)

Step-by-step Solution

Detailed explanation

\(\mathrm{f}(\mathrm{x})=\int_{-\mathrm{x}}^{\mathrm{x}}\left(|\mathrm{t}|-\mathrm{t}^2\right) \mathrm{e}^{-\mathrm{t}^2} \mathrm{dt}\)…