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JEE Mains · Maths · STD 12 - 11. three dimension geometry

જો \((\alpha \  \beta \ \gamma)\left(\begin{array}{ccc}2 & 10 & 8 \\ 9 & 3 & 8 \\ 8 & 4 & 8\end{array}\right)=\left(\begin{array}{llll}0 & 0 & 0\end{array}\right)\) નું સમાધાન કરતુ એક બિંદુ \(P (\alpha, \beta, \gamma)\) એ સમતલ \(2 x+4 y+3 z=5\) પર આવેલ હોય,તો \(6 \alpha+9 \beta+7 \gamma = ...........\)

  1. A \(-1\)
  2. B \(\frac{11}{5}\)
  3. C \(\frac{5}{4}\)
  4. D \(11\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(11\)

Step-by-step Solution

Detailed explanation

\(2 \alpha+4 \beta+3 \gamma=5......(1)\) \(2 \alpha+9 \beta+8 \gamma=0......(2)\) \(10 \alpha+3 \beta+4 \gamma=0......(3)\) \(8 \alpha+8 \beta+8 \gamma=0......(4)\) Subtract \((4)\) from \((2)\) \(-6 \alpha+\beta=0\) \(\beta=6 \alpha\) From equation \((4)\)…
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