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JEE Mains · Maths · STD 11 - 4.1 complex nubers

જો \((\sqrt{3}+\mathrm{i})^{100}=2^{99}(\mathrm{p}+\mathrm{i} \mathrm{q})\) હોય તો \(\mathrm{p}\) અને  \(\mathrm{q}\) એ . . .   સમીકરણના બીજ છે.

  1. A \(x^{2}-(\sqrt{3}-1) x-\sqrt{3}=0\)
  2. B \(x^{2}+(\sqrt{3}+1) x+\sqrt{3}=0\)
  3. C \(x^{2}+(\sqrt{3}-1) x-\sqrt{3}=0\)
  4. D \(x^{2}-(\sqrt{3}+1) x+\sqrt{3}=0\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(x^{2}-(\sqrt{3}-1) x-\sqrt{3}=0\)

Step-by-step Solution

Detailed explanation

\(\left(2 e^{\mathrm{i} \pi / 6}\right)^{100}=2^{99}(\mathrm{p}+\mathrm{i} \mathrm{q})\) \(2^{100}\left(\cos \frac{50 \pi}{3}+\mathrm{i} \sin \frac{50 \pi}{3}\right)=2^{99}(\mathrm{p}+\mathrm{i} \mathrm{q})\)…
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