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JEE Mains · Maths · STD 12 - 13. probability

એક યાદચ્છિક ચલ X નું સંભાવના વિતરણ નીચે આપેલ છે :
X\(4k\)\(\frac{30}{7} k\)\(\frac{32}{7} k\)\(\frac{34}{7} k\)\(\frac{36}{7} k\)\(\frac{38}{7} k\)\(\frac{40}{7} k\)\(6k\)
P(X)\(\frac{2}{15}\)\(\frac{1}{15}\)\(\frac{2}{15}\)\(\frac{1}{5}\)\(\frac{1}{15}\)\(\frac{2}{15}\)\(\frac{1}{5}\)\(\frac{1}{15}\)
જો \(E(X)=\frac{263}{15}\) હોય, તો \(P(X<20)=\) ___ .

  1. A \(\frac{3}{5}\)
  2. B \(\frac{8}{15}\)
  3. C \(\frac{11}{15}\)
  4. D \(\frac{14}{15}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{11}{15}\)

Step-by-step Solution

Detailed explanation

\(E(X)=\sum X_{i}P(X_{i})=\frac{526k}{15\times7}=\frac{263}{15}\Rightarrow k=\frac{7}{2}\)X 14 15 16 17 18 19 20 21 \(P ( X )\) \(\frac{2}{15}\) \(\frac{1}{15}\) \(\frac{2}{15}\) \(\frac{1}{5}\) \(\frac{1}{15}\) \(\frac{2}{15}\) \(\frac{1}{5}\) \(\frac{1}{15}\)…
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