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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

ધારોકે \(f: R \rightarrow R\) એ પ્રત્યેક \(f(x+y)=f(x)+f(y)-1, \forall x, y \in R\) માટે સંબંધ \(f^{\prime}(0)=2\) નું સમાધાન કરતું વિકલનીય વિધ્ય છે. જો \(|f(-2)|\) હોય, તો \(=............\)

  1. A \(6\)
  2. B \(9\)
  3. C \(3\)
  4. D \(12\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(3\)

Step-by-step Solution

Detailed explanation

\(f ( x + y )= f ( x )+ f ( y )-1\) \(f^{\prime}(x)=\lim _{h \rightarrow 0} \frac{f(x+h)-f(x)}{h}\) \(f^{\prime}(x)=\lim _{h \rightarrow 0} \frac{f(h)-f(0)}{h}=f^{\prime}(0)=2\) \(f^{\prime}(x)=2 \Rightarrow d y=2 d x\) \(y =2 x + C\) \(x =0, y =1, c =1\) \(y =2 x +1\)…
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