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JEE Mains · Maths · STD 11 - 8. sequence and series

ધારોકે \([\alpha]\) એ મહત્તમ પૂર્ણાક \(\leq \alpha\) દર્શાવે છે.તો \([\sqrt{1}]+[\sqrt{2}]+[\sqrt{3}]+\ldots+[\sqrt{120}]=.......\)

  1. A \(824\)
  2. B \(825\)
  3. C \(823\)
  4. D \(822\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(825\)

Step-by-step Solution

Detailed explanation

\([\sqrt{1}]+[\sqrt{2}]+[\sqrt{3}]+\ldots \ldots .[\sqrt{120}]\) \(\Rightarrow 1+1+1+2+2+2+2+2+3+3+\ldots \ldots .+\) \(3=7 \text { times }\) \(+4+4+\ldots \ldots .+4=9 \text { times }+\ldots \ldots 10+10+\) \(\ldots \ldots+10=21 \text { times }\)…
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