ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 10. vector algebra

ધારોકે \(|\vec{a}|=2,|\vec{b}|=3\) તથા સદિશો \(\vec{a}\) અને \(\vec{b}\) વચ્ચેનો ખૂણો \(\frac{\pi}{4}\) છે.તો \(|(\vec{a}+2 \vec{b}) \times(2 \vec{a}-3 \vec{b})|^2=........\)

  1. A \(482\)
  2. B \(441\)
  3. C \(841\)
  4. D \(882\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(882\)

Step-by-step Solution

Detailed explanation

\(|\vec{a}|=2,|\vec{b}|=3\) \(|(\vec{a}+2 \vec{b}) \times(2 \vec{a}-3 \vec{b})|^2\) \(|-3 \vec{a} \times \vec{b}+4 \vec{b} \times \vec{a}|^2\) \(|-3 \vec{a} \times \vec{b}-4 \vec{a} \times \vec{b}|^2\) \(|-7 \vec{a} \times \vec{b}|^2\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app