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JEE Mains · Maths · STD 12 - 9. differential equations

ધારો કે \(y=y(x)\) એ વિકલ્પ સમીકરણ \(x^4 d y+\left(4 x^3 y+2 \sin x\right) d x=0, x>0, y\left(\frac{\pi}{2}\right)=0\) નો ઉકેલ છે. તો \(\pi^4 y\left(\frac{\pi}{3}\right)=\) ___ .

  1. A 81
  2. B 92
  3. C 64
  4. D 72
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Answer & Solution

Correct Answer

(A) 81

Step-by-step Solution

Detailed explanation

\( (x^{4}dy+4x^{3}ydx) = -2\sin x dx \) \( \Rightarrow \int d(x^{4}y) = \int -2\sin x dx \) \( \Rightarrow x^{4}y = 2\cos x + c \) \(\Rightarrow x^4 f(x)=2 \cos x+c\) As \(f\left(\frac{\pi}{2}\right)=0\) So, \(c =0\)…
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