ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 9. differential equations

અહી  \(y=y(x)\) એ વિકલ સમીકરણ \(\frac{ dy }{ dx }+\frac{1}{ x ^{2}-1} y =\left(\frac{ x -1}{ x +1}\right)^{\frac{1}{2}}\), \(x>1\) નો ઉકેલ છે કે બિંદુ \(\left(2, \sqrt{\frac{1}{3}}\right)\) માંથી પસાર થાય છે તો \(\sqrt{7} y (8)\) ની કિમંત મેળવો.

  1. A \(11+6 \log _{ e } 3\)
  2. B \(19\)
  3. C \(12-2 \log _{ e } 3\)
  4. D \(19-6 \log _{ e } 3\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(19-6 \log _{ e } 3\)

Step-by-step Solution

Detailed explanation

\(\frac{d y}{d x}+\frac{1}{x^{2}-1} y=\left(\frac{x-1}{x+1}\right)^{\frac{1}{2}}\) \(\frac{d y}{d x}+P y=Q\) \(I \cdot F .= e ^{\int Pdx }=\left(\frac{ x -1}{ x +1}\right)^{\frac{1}{2}}\) \(y\left(\frac{x-1}{x+1}\right)^{\frac{1}{2}}=\int\left(\frac{x-1}{x+1}\right)^{1} d x\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app