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JEE Mains · Maths · STD 11 - Trigonometrical equations

અહી \(S=\left\{\theta \in[0,2 \pi]: 8^{2 \sin ^{2} \theta}+8^{2 \cos ^{2} \theta}=16\right\}\) હોય તો  \(n ( S )+\sum_{\theta \in S}\left(\sec \left(\frac{\pi}{4}+2 \theta\right) \operatorname{cosec}\left(\frac{\pi}{4}+2 \theta\right)\right)\) ની કિમંત મેળવો.

  1. A \(0\)
  2. B \(-2\)
  3. C \(-4\)
  4. D \(12\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-4\)

Step-by-step Solution

Detailed explanation

\(8^{2 \sin ^{2} \theta}+8^{2-2 \sin ^{2} \theta}=16\) \(y+\frac{64}{y}=16\) \(\Rightarrow y =8\) \(\Rightarrow \sin ^{2} \theta=1 / 2\) \(n ( S )+\sum_{\theta \in S} \frac{1}{\cos (\pi / 4+2 \theta) \sin (\pi / 4+2 \theta)}\) \(=4+(-2) \times 4=-4\)
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