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JEE Mains · Maths · STD 11 - 12. limits

અહી \(f(x)=x^{6}+2 x^{4}+x^{3}+2 x+3, x \in R\) આપેલ છે તો પ્રાકૃતિક સંખ્યા \(\mathrm{n}\) ની કઈ કિમંત માટે \(\lim _{x \rightarrow 1} \frac{\mathrm{x}^{\mathrm{n}} \mathrm{f}(1)-\mathrm{f}(\mathrm{x})}{\mathrm{x}-1}=44\)  થાય.

  1. A \(6\)
  2. B \(7\)
  3. C \(8\)
  4. D \(9\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(7\)

Step-by-step Solution

Detailed explanation

\(f(n)=x^{6}+2 x^{4}+x^{3}+2 x+3\) \(\lim _{x \rightarrow 1} \frac{x^{n} f(1)-f(x)}{x-1}=44\) \(\lim _{x \rightarrow 1} \frac{9 x^{n}-\left(x^{6}+2 x^{4}+x^{3}+2 x+3\right)}{x-1}=44\) \(\lim _{x \rightarrow 1} \frac{9 n x^{n-1}-\left(6 x^{5}+8 x^{3}+3 x^{2}+2\right)}{1}=44\)…
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