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JEE Mains · Maths · STD 11 - 6. permutation and combination

અહી \(\left(\begin{array}{l}n \\ k\end{array}\right)\) એ  \({ }^{n} C_{k}\) દર્શાવે છે અને \(\left[\begin{array}{l} n \\ k \end{array}\right]=\left\{\begin{array}{cc}\left(\begin{array}{c} n \\ k \end{array}\right), & \text { if } 0 \leq k \leq n \\ 0, & \text { otherwise }\end{array}\right.\) છે. જો \(A_{k}=\sum_{i=0}^{9}\left(\begin{array}{l}9 \\ i\end{array}\right)\left[\begin{array}{c}12 \\ 12-k+i\end{array}\right]+\sum_{i=0}^{8}\left(\begin{array}{c}8 \\ i\end{array}\right)\left[\begin{array}{c}13 \\ 13-k+i\end{array}\right]\) અને  \(A_{4}-A_{3}=190 \mathrm{p}\) હોય તો  \(p\) ની કિમંત મેળવો.

  1. A \(50\)
  2. B \(51\)
  3. C \(48\)
  4. D \(49\)
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Answer & Solution

Correct Answer

(D) \(49\)

Step-by-step Solution

Detailed explanation

\(\mathrm{A}_{\mathrm{k}}=\sum_{\mathrm{i}=0}^{9}{ }^{9} \mathrm{C}_{\mathrm{i}}{ }^{12} \mathrm{C}_{\mathrm{k}-\mathrm{i}}+\sum_{\mathrm{i}=0}^{8}{ }^{8} \mathrm{C}_{\mathrm{i}}{ }^{13} \mathrm{C}_{\mathrm{k}-\mathrm{i}}\)…
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