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JEE Mains · Maths · STD 12 - 7.2 definite integral

\(\frac{24}{\pi} \int_{0}^{\sqrt{2}} \frac{\left(2-x^{2}\right) d x}{\left(2+x^{2}\right) \sqrt{4+x^{4}}}=\dots\dots\dots\) 

  1. A \(1\)
  2. B \(2\)
  3. C \(4\)
  4. D \(3\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(3\)

Step-by-step Solution

Detailed explanation

\(\frac{24}{\pi} \int_{0}^{\sqrt{2}} \frac{\left(2-x^{2}\right)}{\left(x^{2}+2\right) \sqrt{4+x^{4}}} d x\) \(\frac{24}{\pi} \int_{0}^{\sqrt{2}} \frac{x^{2}\left(\frac{2}{x^{2}}-1\right) d x}{x\left(x+\frac{2}{x}\right) \times x \sqrt{\frac{4}{x^{2}}+x^{2}}}\)…
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