WBJEE · Physics · Electromagnetic Induction
Two straignt conducting plates form an angle \(\theta\) where their ends are joined. A conducting bar in contact with the plates and forming an isosceles triangle with them starts at the vertex at time \(t=0\) and moves with constant velocity \(\vec{v}\) to the right as shown in figure. A magnetic field \(\vec{B}\) points out of the page. The magnitude of emf induced at \(t=1\) second will be

- A \(\mathrm{Bv} \tan \frac{\theta}{2}\)
- B \(\mathrm{Bv}^2 \tan \frac{\theta}{2}\)
- C \(2 \mathrm{Bv}^2 \tan \frac{\theta}{2}\)
- D \(2 \mathrm{Bv}^2 \sin \frac{\theta}{2}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{Bv}^2 \tan \frac{\theta}{2}\)
Step-by-step Solution
Detailed explanation
Hint : \(\ell=2 \mathrm{vt} \tan \frac{\theta}{2}\) \[ \varepsilon=\mathrm{B} \ell \mathrm{v}=2 \mathrm{Bv} \mathrm{v}^2 \tan \frac{\theta}{2} \]
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