WBJEE · Maths · Binomial Theorem
The remainder when \(7^{7^{7^{...7}}}(22\) times 7\()\) is divided by 48 is
- A 21
- B 7
- C 47
- D 1
Answer & Solution
Correct Answer
(B) 7
Step-by-step Solution
Detailed explanation
\(7^{7^{7-7}}=7^{2 \mathrm{~m}+1}=7(49)^{\mathrm{m}}=7(1+48)^{\mathrm{m}}=48 \mathrm{k}+7\)
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