WBJEE · Physics · Center of Mass Momentum and Collision
Two particles have masses \(\mathrm{m} \& 4 \mathrm{~m}\) and their kinetic energies are in the ratio \(2: 1\). What is the ratio of their linear momenta?
- A \(\frac{1}{\sqrt{2}}\)
- B \(\frac{1}{2}\)
- C \(\frac{1}{4}\)
- D \(\frac{1}{16}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
\(\frac{K E_1}{K E_2}=\frac{\frac{p_1^2}{2 m}}{\frac{p_2^2}{2 \times 4 m}}=\frac{2}{1} \Rightarrow \frac{p_1}{p_2}=\frac{1}{\sqrt{2}}\)
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