WBJEE · Maths · Limits
Let \(f(x)=\frac{\sqrt{x+3}}{x+1}\) then the value of \(\underset{x \rightarrow-3-0}{\operatorname{Lt}} f(x)\) is
- A 0
- B does not exist
- C \(\frac{1}{2}\)
- D \(-\frac{1}{2}\)
Answer & Solution
Correct Answer
(B) does not exist
Step-by-step Solution
Detailed explanation
Hints : Because on left hand side of 3 function is not defined.
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