WBJEE · Maths · Application of Derivatives
The co-ordinates of the point on the curve \(y=x^2-3 x+2\) where the tangent is perpendicular to the straight line \(y=x\) are
- A \((0,2)\)
- B \((1,0)\)
- C \((-1,6)\)
- D \((2,-2)\)
Answer & Solution
Correct Answer
(B) \((1,0)\)
Step-by-step Solution
Detailed explanation
Hints: \(y=x^2-3 x+2\) \(\frac{d y}{d x}=2 x-3=-1 \Rightarrow x=1\) at \(x=1, y=0\) \(\therefore\) Point is \((1,0)\)
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