WBJEE · Physics · Mathematics in Physics
The vectors \(\mathrm{A}\) and \(\mathrm{B}\) are such that \(|\mathbf{A}+\mathbf{B}|=|\mathbf{A}-\mathbf{B}| .\) The angle between the two vectors will be
- A \(0^{\circ}\)
- B \(60^{\circ}\)
- C \(90^{\circ}\)
- D \(45^{\circ}\)
Answer & Solution
Correct Answer
(C) \(90^{\circ}\)
Step-by-step Solution
Detailed explanation
Given, \(|A+B|=|A-B|\) \(\therefore \quad(A+B)^{2}=(A-B)^{2}\) \(A^{2}+B^{2}+2 A B \cos \theta=A^{2}+B^{2}-2 A B \cos \theta\) \(2 A B \cos \theta+2\) AB \(\cos \theta=0\) \(4 A B \cos \theta=0\) Here, \(\quad A \neq 0, B \neq 0\) \(\therefore \quad \cos \theta=0\)…
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