WBJEE · Physics · Kinetic Theory of Gases
The r.m.s speed of the molecules of a gas at \(100^{\circ} \mathrm{C}\) is \(v .\) The temperature at which the r.m.s. speed will be \(\sqrt{3} v\) is
- A \(546^{\circ} \mathrm{C}\)
- B \(646^{\circ} \mathrm{C}\)
- C \(746^{\circ} \mathrm{C}\)
- D \(846^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(D) \(846^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\(v_{\text {tms }}=\sqrt{\frac{3 R T}{M}}\) Given, \(\quad T=100^{\circ} \mathrm{C}=373 \mathrm{K}\) \(\therefore \quad v=\sqrt{\frac{3 R \times 373}{M}}\) For \(\quad \sqrt{3} v=\sqrt{\frac{3 R T}{M}}\)…
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