WBJEE · Physics · Atomic Physics
The minimum wavelength of Lyman series lines is \(P\), then the maximum wavelength of these lines is
- A \(\frac{4 \mathrm{P}}{3}\)
- B 2 P
- C \(\frac{2 P}{3}\)
- D \(\quad \infty\)
Answer & Solution
Correct Answer
(A) \(\frac{4 \mathrm{P}}{3}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \lambda_{\min }=\mathrm{P} \\ & \frac{\mathrm{hc}}{\lambda_{\min }}=\mathrm{c}_1\left(\frac{1}{1}-\frac{1}{\infty}\right) \\ & \lambda_{\min }=\frac{\mathrm{hc}}{\mathrm{c}_1} \\ & \frac{\mathrm{hc}}{\lambda_{\max…
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