WBJEE · Physics · Dual Nature of Matter
The de-Broglie wavelength of an electron (mass \(=1 \times 10^{-30} \mathrm{kg},\) charge \(\left.=16 \times 10^{-19} \mathrm{C}\right)\) with a kinetic energy of \(200 \mathrm{eV}\) is (Planck's constant \(=6.6 \times 10^{-34} \mathrm{Js}\)
- A \(9.60 \times 10^{-11} \mathrm{m}\)
- B \(8.25 \times 10^{-11} \mathrm{m}\)
- C \(6.25 \times 10^{-11} \mathrm{m}\)
- D \(5.00 \times 10^{-11} \mathrm{m}\)
Answer & Solution
Correct Answer
(B) \(8.25 \times 10^{-11} \mathrm{m}\)
Step-by-step Solution
Detailed explanation
The de-Broglie wavelength, \(\lambda=\frac{h}{\sqrt{2 m k}}\) Given, \[ h=6.6 \times 10^{-34} \mathrm{J}-\mathrm{s} \] \[ \begin{aligned} m &=1 \times 10^{-30} \mathrm{kg} \\ K=200 \mathrm{eV} &=200 \times 1.6 \times 10^{-19} \mathrm{J} \end{aligned} \] Substituting all these…
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