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WBJEE · Physics · Laws of Motion

The minimum force required to start pushing a body up a rough (having co-efficient of friction \(\mu\) ) inclined plane is \(\vec{F}_1\) while the minimum force needed to prevent it from sliding is \(\vec{F}_2\). If the inclined plane makes an angle \(\theta\) with the horizontal such that \(\tan \theta=2 \mu\), then the ratio \(F_1 / F_2\) is

  1. A 4
  2. B 1
  3. C 2
  4. D 3
Verified Solution

Answer & Solution

Correct Answer

(D) 3

Step-by-step Solution

Detailed explanation

When body is being prevented from sliding down \(\begin{aligned} & F_{\min }=F_2=m g \sin \theta-\mu m g \cos \theta \\ & F_2=m g \sin \theta-\mu m g \cos \theta\end{aligned}\) When body is pushed up friction acts downward…