WBJEE · Physics · Laws of Motion
The minimum force required to start pushing a body up a rough (having co-efficient of friction \(\mu\) ) inclined plane is \(\vec{F}_1\) while the minimum force needed to prevent it from sliding is \(\vec{F}_2\). If the inclined plane makes an angle \(\theta\) with the horizontal such that \(\tan \theta=2 \mu\), then the ratio \(F_1 / F_2\) is
- A 4
- B 1
- C 2
- D 3
Answer & Solution
Correct Answer
(D) 3
Step-by-step Solution
Detailed explanation
When body is being prevented from sliding down \(\begin{aligned} & F_{\min }=F_2=m g \sin \theta-\mu m g \cos \theta \\ & F_2=m g \sin \theta-\mu m g \cos \theta\end{aligned}\) When body is pushed up friction acts downward…
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