WBJEE · Physics · Magnetic Effects of Current
A straight conductor \(0.1 \mathrm{m}\) long moves in uniform magnetic field \(0.1 \mathrm{T}\). The velocity the conductor is \(15 \mathrm{m} / \mathrm{s}\) and is directer perpendicular to the field. The emf inducod between the two ends of the conductor is
- A \(0.10 \mathrm{V}\)
- B \(0.15 \mathrm{V}\)
- C \(1.50 \mathrm{V}\)
- D \(15.00 \mathrm{v}\)
Answer & Solution
Correct Answer
(B) \(0.15 \mathrm{V}\)
Step-by-step Solution
Detailed explanation
Given, length of conductor \(l=0.1 \mathrm{m}\) Mangetic field. \(B=0.1 \mathrm{T}\) Velocity of conductor, \(v=15 \mathrm{m} / \mathrm{s}\) The angle between \(\mathbf{v}\) and \(\mathbf{B}\) is \(90^{\circ}\) When \(\mathbf{v}\) and \(\mathbf{B}\) are mutually perpendicular,…
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