WBJEE · Physics · Capacitance
The figure shows two identical parallel plate capacitors \(A\) and \(B\) of capacitances \(C\) connected to a battery. The key \(\mathrm{K}\) is initially closed. The switch is now opened and the free spaces between the plates of the capacitors are filled with a dielectric constant 3. Then which of the following statement (s) is/are true?
- A Which the switch is closed, total energy stored in the two capacitors is \(\mathrm{CV}^2\)
- B When the switch is opened, no charge is stored in the capacitor B
- C When the switch is opened, energy stored in the capacitor \(\mathrm{B}\) is \(\frac{3}{2} \mathrm{CV}^2\)
- D When the switch is opened, total energy stored in two capacitors is \(\frac{5}{2} \mathrm{CV}^2\)
Answer & Solution
Correct Answer
(D) When the switch is opened, total energy stored in two capacitors is \(\frac{5}{2} \mathrm{CV}^2\)
Step-by-step Solution
Detailed explanation
Hint : \(\begin{aligned} & \mathrm{U}=\frac{1}{2} \times 2 \mathrm{CV}^2 \\ & =\mathrm{CV}^2\end{aligned}\)…
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