WBJEE · Physics · Alternating Current
In a series LCR circuit, the rms voltage across the resistor and the capacitor are 30 V and 90 V respectively. If the applied voltage is \(50 \sqrt{2} \sin \omega t\), then the peak voltage across the inductor is
- A 70 V
- B 50 V
- C \(70 \sqrt{2} \mathrm{~V}\)
- D \(50 \sqrt{2} \mathrm{~V}\)
Answer & Solution
Correct Answer
(D) \(50 \sqrt{2} \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Hint: \(\sqrt{30^2+\left(90-V_{\mathrm{L}}\right)^2}=50\) \[ \begin{aligned} & \Rightarrow \mathrm{V}_{\mathrm{L}}=50 \mathrm{~V} \\ & =\left(\mathrm{V}_{\mathrm{L}}\right)_{\max }=50 \sqrt{2} \mathrm{~V} \end{aligned} \]
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