WBJEE · Physics · Rotational Motion
A small sphere of mass \(m\) and radius \(r\) slides down the smooth surface of a large hemispherical bowl of radius \(R\). If the sphere starts sliding from rest, the total kinetic energy of the sphere at the lowest point \(A\) of the bowl will be [given, moment of inertia of sphere \(\left.=\frac{2}{5} \mathrm{mr}^2\right]\)

- A \(\quad m g(R-r)\)
- B \(\frac{7}{10} m g(R-r)\)
- C \(\frac{2}{7} m g(R-r)\)
- D \(\frac{10}{7} m g(R-r)\)
Answer & Solution
Correct Answer
(A) \(\quad m g(R-r)\)
Step-by-step Solution
Detailed explanation
Hint: \(m g(R-r)=K_f\)
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