WBJEE · Physics · Electromagnetic Induction
The current through a coil of self inductance \(\mathrm{L}=2 m \mathrm{H}\) is given by \(\mathrm{I}=t^2 e^{-t}\) at time \(t\). How long it will take to make the e \(\mathrm{m} . f\) zero?
- A \(1 \mathrm{~s}\)
- B \(2 \mathrm{~s}\)
- C \(3 \mathrm{~s}\)
- D \(4 \mathrm{~s}\)
Answer & Solution
Correct Answer
(B) \(2 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
Hints: \(\mathrm{I}=t^2 e^{-t}\) \[ \begin{aligned} & \frac{d \mathrm{I}}{d t}=2 t e^{-t}-e^{-t} t^2=e^{-t} t(2-t) \\ & e=-\mathrm{L} \frac{d \mathrm{I}}{d t} \\ & \Rightarrow \frac{d \mathrm{I}}{d t}=0 \Rightarrow e^{-t} t(2-t)=0 \\ & t=2 \mathrm{sec} \end{aligned} \]
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