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WBJEE · Physics · Electromagnetic Induction

The current through a coil of self inductance \(\mathrm{L}=2 m \mathrm{H}\) is given by \(\mathrm{I}=t^2 e^{-t}\) at time \(t\). How long it will take to make the e \(\mathrm{m} . f\) zero?

  1. A \(1 \mathrm{~s}\)
  2. B \(2 \mathrm{~s}\)
  3. C \(3 \mathrm{~s}\)
  4. D \(4 \mathrm{~s}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2 \mathrm{~s}\)

Step-by-step Solution

Detailed explanation

Hints: \(\mathrm{I}=t^2 e^{-t}\) \[ \begin{aligned} & \frac{d \mathrm{I}}{d t}=2 t e^{-t}-e^{-t} t^2=e^{-t} t(2-t) \\ & e=-\mathrm{L} \frac{d \mathrm{I}}{d t} \\ & \Rightarrow \frac{d \mathrm{I}}{d t}=0 \Rightarrow e^{-t} t(2-t)=0 \\ & t=2 \mathrm{sec} \end{aligned} \]