WBJEE · Maths · Differential Equations
If \(x^2+y^2=1\) then
- A \(y y^{\prime \prime}-\left(2 y^{\prime}\right)^2+1=0\)
- B \(y y^{\prime \prime}+\left(y^{\prime}\right)^2+1=0\)
- C \(y y^{\prime \prime}-\left(y^{\prime}\right)^2-1=0\)
- D \(y y^{\prime \prime}+\left(2 y^{\prime}\right)^2+1=0\)
Answer & Solution
Correct Answer
(B) \(y y^{\prime \prime}+\left(y^{\prime}\right)^2+1=0\)
Step-by-step Solution
Detailed explanation
Hints: \(2 x+2 y y^{\prime}=0\) \[ \begin{aligned} & x+y y^{\prime}=0 \\ & 1+y y^{\prime \prime}+\left(y^{\prime}\right)^2=0 \end{aligned} \]
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