WBJEE · Physics · Semiconductors
Manufacturers supply a zener diode with zener voltage \(\mathrm{V}_{\mathrm{z}}=5.6 \mathrm{~V}\) and maximum power dissipation \(\mathrm{P}_{\mathrm{z} \max }=\frac{1}{4} \mathrm{~W}\). This zener diode is used in the following circuit. Calculate the minimum value of the resistance \(R_s\) in the circuit so that the zener diode will not burn when the input voltage is \(\mathrm{V}_{\mathrm{in}}=10 \mathrm{~V}\).
- A \(98.56 \Omega\)
- B \(170.52 \Omega\)
- C \(306.21 \Omega\)
- D \(412.37 \Omega\)
Answer & Solution
Correct Answer
(A) \(98.56 \Omega\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{ll}V_z=5.6 \mathrm{~V} & \mathrm{P}_{\mathrm{z} \max }=\frac{1}{4} \mathrm{~W} \\ \mathrm{~V}_{\text {in }}=10 \mathrm{~V} . & \end{array}\) \(P=V_z I_z \Rightarrow \frac{1}{4}=5.6 \times I_z \quad I_Z=\frac{1}{4 \times 5.6}=I_s\) Now,…
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