WBJEE · Physics · Thermodynamics
A given quantity of gas is taken from \(A\) to \(C\) in two ways; \(a\) ) directly from \(A \rightarrow C\) along a straight line and \(b\) ) in two steps, from \(A \rightarrow B\) and then from \(B \rightarrow C\). Work done and heat absorbed along the direct path \(A \rightarrow C\) is \(200 \mathrm{~J}\) and \(280 \mathrm{~J}\) respectively
- A \(80 \mathrm{~J}\)
- B 0
- C \(160 \mathrm{~J}\)
- D \(120 \mathrm{~J}\)
Answer & Solution
Correct Answer
(C) \(160 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Hint : \(\Delta W=200 \mathrm{~J} \quad \Delta Q=280 \mathrm{~J} \quad\) for path \(A C\) \(\therefore \quad \Delta U=\Delta Q-\Delta W=280-200=80 \mathrm{~J}\) \((\Delta U)\) is same for both paths. \(\therefore \Delta Q=\Delta W+\Delta U=80+80=160 \mathrm{~J}\)
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