WBJEE · Physics · Current Electricity
A wire of resistance \(5 \Omega\) is drawn out so that its new length is 3 times its original length. What is the reistance of the new wire?
- A \(45 \Omega\)
- B \(15 \Omega\)
- C \(5 / 3 \Omega\)
- D \(5 \Omega\)
Answer & Solution
Correct Answer
(A) \(45 \Omega\)
Step-by-step Solution
Detailed explanation
\(\left(\frac{r_1}{r_2}\right)^2=\left(\frac{\ell_2}{\ell_1}\right)=\frac{3 \ell}{\ell}=3\) \(\left(\frac{R_2}{R_1}\right)=\frac{\ell_2}{\ell_1} \times \frac{A_1}{A_2}=3 \times\left(\frac{r_1}{r_2}\right)^2=3 \times 3 \Rightarrow R_2=45\)
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