WBJEE · Physics · Units and Dimensions
A particle of mass ' \(m\) ' moves in one dimension under the action of a conservative force whose potential energy has the form of \(U(x)=-\frac{\alpha x}{x^2+\beta^2}\) where \(\alpha\) and \(\beta\) are dimensional parameters. The angular frequency of the oscillation is proportional to
- A \(\sqrt{\frac{\alpha^3}{m \beta^4}}\)
- B \(\sqrt{\frac{\alpha}{m \beta^4}}\)
- C \(\sqrt{\frac{\alpha}{m \beta^3}}\)
- D \(\sqrt{\frac{\alpha}{m \beta^6}}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{\frac{\alpha}{m \beta^3}}\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} \text { Hint: } U & =-\frac{\alpha x}{x^2+\beta^2} \\ \text { here, }[\beta] & =[L] \\ {[\alpha] } & =\left[M^3 T^{-2}\right] \end{aligned} \] only option (C) has dimension of \(\frac{1}{\mathrm{~T}}\)
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