WBJEE · Physics · Units and Dimensions
If \(x=a t+b t^{2},\) where \(x\) is in metre \((\mathrm{m})\) and \(t\) is in hour \((\mathrm{h})\), then unit of \(b\) will be
- A \(\frac{\mathrm{m}^{2}}{\mathrm{h}}\)
- B \(m\)
- C \(\frac{m}{h}\)
- D \(\frac{m}{h^{2}}\)
Answer & Solution
Correct Answer
(D) \(\frac{m}{h^{2}}\)
Step-by-step Solution
Detailed explanation
Given, \(x=a t+b t^{2}\) \(\begin{array}{l} {[x]=\left[b t^{2}\right]} \\ \text { Unit of } b=\frac{x}{t^{2}}=\frac{\text { metre }}{(h)^{2}}=\frac{m}{h^{2}} \end{array}\)
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