WBJEE · Physics · Atomic Physics
If the potential energy of a hydrogen atom in the first excited state is assumed to be zero, then the total energy of \(n\) \(=\infty\) state is,
- A \(3.4 \mathrm{eV}\)
- B \(6.8 \mathrm{eV}\)
- C 0
- D \(\infty\)
Answer & Solution
Correct Answer
(B) \(6.8 \mathrm{eV}\)
Step-by-step Solution
Detailed explanation
Hint : Potential energy in 1 st emited stage \(\left(\mathrm{U}_2\right)=-6.8 \mathrm{eV}\). When \(U_2\) is assumed to be zero then potential energy in \((n=\infty)\) will be \(6.8 \mathrm{eV}\) so, total energy for \((n=\infty)=6.8 \mathrm{eV}\)
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