WBJEE · Chemistry · Solid State
What is the edge length of the unit cell of a body centred cubic crystal of an element whose atomic radius is \(75 \mathrm{pm}\) ?
- A \(170 \mathrm{pm}\)
- B \(175 \mathrm{pm}\)
- C \(178 \mathrm{pm}\)
- D \(173.2 \mathrm{pm}\)
Answer & Solution
Correct Answer
(D) \(173.2 \mathrm{pm}\)
Step-by-step Solution
Detailed explanation
Hint : In BCC, \(4 r=\sqrt{3} a\) \(\therefore \mathrm{a}=\frac{4 \mathrm{r}}{\sqrt{3}}=\frac{4 \times 75}{\sqrt{3}}=\frac{300}{\sqrt{3}}=\sqrt{3} \times 100 \mathrm{pm}=173.2 \mathrm{pm}\)
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