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WBJEE · Chemistry · Solid State

What is the edge length of the unit cell of a body centred cubic crystal of an element whose atomic radius is \(75 \mathrm{pm}\) ?

  1. A \(170 \mathrm{pm}\)
  2. B \(175 \mathrm{pm}\)
  3. C \(178 \mathrm{pm}\)
  4. D \(173.2 \mathrm{pm}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(173.2 \mathrm{pm}\)

Step-by-step Solution

Detailed explanation

Hint : In BCC, \(4 r=\sqrt{3} a\) \(\therefore \mathrm{a}=\frac{4 \mathrm{r}}{\sqrt{3}}=\frac{4 \times 75}{\sqrt{3}}=\frac{300}{\sqrt{3}}=\sqrt{3} \times 100 \mathrm{pm}=173.2 \mathrm{pm}\)