WBJEE · Physics · Rotational Motion
Four small objects each of mass \(m\) are fixed at the corners of a rectangular wire-frame of negligible mass and of sides \(a\) and \(b(a>b)\) If the wire frame is now roated about an axig passing along the side of length \(b,\) then the moment of inertia of the system for this axis of rotation is
- A \(2 \mathrm{ma}^{2}\)
- B \(4 \mathrm{ma}^{2}\)
- C \(2 m\left(a^{2}+b^{2}\right)\)
- D \(2 m\left(a^{2}-b^{2}\right)\)
Answer & Solution
Correct Answer
(A) \(2 \mathrm{ma}^{2}\)
Step-by-step Solution
Detailed explanation
The given situation can be shown as Moment of inertia of the system about side of length \(b\) say \(C D\) is \(=M .I .\) of mass at \(A\) about \(C D+M .I .\) of mass at \(B\) mass ot \(D\) about \(C D\)…
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