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WBJEE · Maths · Quadratic Equation

The quadratic equation
\(2 x^{2}-\left(a^{3}+8 a-1\right) x+a^{2}-4 a=0\) has roots of opposite sign. Then,

  1. A \(a \leq 0\)
  2. B \(0 < a < 4\)
  3. C \(4 \leq a < 8\)
  4. D \(a \geq 8\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(0 < a < 4\)

Step-by-step Solution

Detailed explanation

Since, roots are opposite sign. Product of the roots \(\leq 0\) \(\begin{array}{ll}\Rightarrow & a^{2}-4 a < 0 \\ \Rightarrow & a(a-4) < 0 \\ \Rightarrow & 0 < a < 4\end{array}\)
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