WBJEE · Maths · Quadratic Equation
The quadratic equation
\(2 x^{2}-\left(a^{3}+8 a-1\right) x+a^{2}-4 a=0\) has roots of opposite sign. Then,
- A \(a \leq 0\)
- B \(0 < a < 4\)
- C \(4 \leq a < 8\)
- D \(a \geq 8\)
Answer & Solution
Correct Answer
(B) \(0 < a < 4\)
Step-by-step Solution
Detailed explanation
Since, roots are opposite sign. Product of the roots \(\leq 0\) \(\begin{array}{ll}\Rightarrow & a^{2}-4 a < 0 \\ \Rightarrow & a(a-4) < 0 \\ \Rightarrow & 0 < a < 4\end{array}\)
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