WBJEE · Physics · Electrostatics
Consider two concentric spherical metal shells of radii \(r_{1}\) and \(r_{2}\left(r_{2}>r_{1}\right)\). If the outer shell has a charge \(q\) and the inner one is grounded, the charge on the inner shell is
- A \(\frac{-r_{2}}{5}, q\)
- B zero
- C \(\frac{-r_{1}}{r_{2}} q\)
- D \(-q\)
Answer & Solution
Correct Answer
(C) \(\frac{-r_{1}}{r_{2}} q\)
Step-by-step Solution
Detailed explanation
Let, the charge on the inner shell be \(q^{\prime}\) The total charge will be zero So, \(\frac{k q^{\prime}}{r_{1}}+\frac{k q}{r_{2}}=0\) \(\left(\because r_{2}>r_{1}\right)\) \(\Rightarrow \quad q^{\prime}=-\frac{K q / r_{2}}{K / r_{1}}\)…
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