WBJEE · Physics · Magnetic Effects of Current
An electron enters an electric field having
intensity \(\mathbf{E}=3 \overrightarrow{\mathbf{i}}+6 \hat{\mathbf{j}}+2 \hat{\mathbf{k}} \cdot \mathbf{V} \mathbf{m}^{-1}\) and magnetic
field having induction \(\mathrm{B}=2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}\) T with a velocity \(\mathbf{v}=2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}\) ms \(^{-1}\). The magnitude of the force acting on the electron is (Given, \(\left.e=-1.6 \times 10^{-19} \mathrm{C}\right)\)
- A \(2.02 \times 10^{-18} \mathrm{N}\)
- B \(5.16 \times 10^{-16} \mathrm{N}\)
- C \(3.72 \times 10^{-17} \mathrm{N}\)
- D None of the above
Answer & Solution
Correct Answer
(D) None of the above
Step-by-step Solution
Detailed explanation
Given, \(E=3 i+6 j+2 \hat{k} \vee / m\) \[ \begin{array}{l} B=2 \hat{i}+3 \hat{j} T \\ v=2 \hat{i}+3 \hat{j} m / s \\ e=-1.6 \times 10^{-10} C \end{array} \] The magnitude of electric field…
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