WBJEE · Physics · Laws of Motion
A cricket ball of mass \(0.25 \mathrm{~kg}\) with speed \(10 \mathrm{~m} / \mathrm{s}\) collides with a bat and returns with same speed within \(0.01 \mathrm{~S}\). The force acted on bat is
- A \(25 \mathrm{~N}\)
- B \(50 \mathrm{~N}\)
- C \(250 \mathrm{~N}\)
- D \(500 \mathrm{~N}\)
Answer & Solution
Correct Answer
(D) \(500 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Hints: \(\Delta \mathrm{P}=2 \mathrm{mV}=2 \times 0.25 \times 10=5 \frac{\mathrm{kgm}}{\mathrm{s}}\) \(\mathrm{F}=\frac{\Delta \mathrm{P}}{\Delta \mathrm{t}}=\frac{5}{0.01}=500 \mathrm{~N}\)
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