WBJEE · Physics · Kinetic Theory of Gases
Air inside a closed container is saturated with water vapour. The air pressure is \(\mathrm{p}\) and the saturated vapour pressure of water is \(\bar{p}\). If the mixture is compressed to one half of its volume by maintaining temperature constant, the pressure becomes
- A \(2(\mathrm{p}+\overline{\mathrm{p}})\)
- B \(2 \mathrm{p}+\overline{\mathrm{p}}\)
- C \((\mathrm{p}+\overline{\mathrm{p}}) / 2\)
- D \(\mathrm{p}+2 \overline{\mathrm{p}}\)
Answer & Solution
Correct Answer
(B) \(2 \mathrm{p}+\overline{\mathrm{p}}\)
Step-by-step Solution
Detailed explanation
Hints: \(P_f=2 P+\bar{P}\) Saturated vapour pressure will not change if temperature remains constant
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