WBJEE · Chemistry · States of Matter
Case \(-1:\) An ideal gas of molecular weight \(M\) at temperature \(T\).
Case \(-2:\) Another ideal gas of molecular weight \(2 \mathrm{M}\) at temperature \(\mathrm{T} / 2\)
Identify the correct statement in context of above two cases.
- A Average kinetic energy and avereage speed will be the same in the two cases
- B Both the averages are halved
- C Both the averages are doubled
- D Only average speed is halved in the second case
Answer & Solution
Correct Answer
(B) Both the averages are halved
Step-by-step Solution
Detailed explanation
Hint : As temperature is halved, average \(K E\) is halved. Average speed \((C) \propto \sqrt{\frac{T}{M}}\) In case \(-I,(C) \propto \sqrt{\frac{T}{M}}\) \(\text { In case }-II ~(C) \propto \sqrt{\frac{T}{2 \times 2 M}}=\frac{1}{2} \sqrt{\frac{T}{M}}\) So average speed is also…
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